Exemple of changing to a
reference frame in the past
Suppose we search a galaxy and we detect the
Lyα emission being three times greater than the Lyα in our world. The
wavelenght is exactly 3647,07 Â.
The H Lyα in our frame is 1215,69 Â.
So, the apparent redshift Z(f) is
Lyα(f)/Lyα(o)-1 = 2
The constant Kh is (1+Z(f))^(1/3) = (1+2)^(1/3)
=1,44224957
So, Kh=1,44224957
Now we can determine the main constants of the
reference frame in the past;
formula* local
frame(o) past
frame(f)
h(f) h(o) x (Kh) 6,62606957E-34 Js 9,5564460E-34 Js
Lyα(f) Lyα(o) x (Kh)³ 1215,69 Â 3647,07 Â
r(f) r(o)
x (Kh)² 0,529 Â 1,1007 Â
E(f)
E(o) / (Kh)² 10,204 eV 4,906 eV
WDC(f) WDC(o)
x (Kh) 0,0028978 mK 0,0041796 mK
R∞(f) R∞(o) / (Kh)³ 10973730,68 m-¹ 3657910,22 m-¹
T(f) T(o) / (Kh)² 23836 ºK 11459 ºK
(f) Observed frame in the past
(o) Local frame at the present
* simplified
formula
If we
consider Ho=71 km/s/mpc and assume it is enough to determine the distance, we
have:
distance=
3380,3 mpc = 11,02 GLY
time (past)
= 11,02 Gyr
Ho= Hublle
constant